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13 de sept. de 2011 · A non-virtual destructor signifies that a class should not be used as a base-class. Not really; a non-virtual destructor signifies that deleting an instance of derived via a base pointer will not work. For example: class Base {}; class Derived : public Base {}; Base* b = new Derived; delete b; // Does not call Derived's destructor!
8 de ene. de 2012 · Non-virtual member functions are resolved statically. member function are binding statically at compile-time based on the type of the pointer (or reference) to the object. In contrast, virtual member functions are binding dynamically at run-time.
3 de feb. de 2016 · If you have a Base* variable, then calling non-virtual functions will call the Base functions. That's the difference between virtual and non-virtual; calling a virtual function always calls the function that is appropriate for the object.
Experienced C++ programmers will sometimes redefine a non-virtual function for efficiency (e.g., if the derived class implementation can make better use of the derived class’s resources) or to get around the hiding rule.
When you call a non-virtual function, the compiler obviously doesn’t use the virtual-function mechanism. Instead it calls the function by name, using the fully qualified name of the member function.
1 de jun. de 2022 · The virtual specifier specifies that a non-static member function is virtual and supports dynamic dispatch. It may only appear in the decl-specifier-seq of the initial declaration of a non-static member function (i.e., when it is declared in the class definition).
Without virtual member functions: #include <iostream> struct X { void f() { std::cout << "X::f()\n"; } }; struct Y : X { void f() { std::cout << "Y::f()\n"; } }; void call(X& a) { a.f(); } int main() { X x; Y y; call(x); // outputs "X::f()" call(y); // outputs "X::f()" }
