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Problem 3: Densities of sodium for three different temperatures are given т р 94°C 929 kg/m3 200°C 889 kg/m3 371°C 860 kg/m3 a) Find the interpolating polynomial of max degree that can be obtained using Lagrange interpolation and hence predict the density of sodium at 250°C.
Question. Transcribed Image Text: The following table gives the density of sodium dt three temperatures Temp (°C) 94 205 371 Density (kg/m³) 929.0 902 0 860.0 Calculate the density for T = 251°C using a quadratric interpolation, by hand. Mathlab scop to cheill your result. Expert Solution.
Q\#1 Densities of sodium for three different temperatures are given \begin{tabular}{|c|c|} \hline $\boldsymbol{T}$ & $\boldsymbol{\rho}$ \\ \hline $94^{\circ} \mathrm{C}$ & $929 \mathrm{~kg} / \boldsymbol{m}^{3}$ \\ \hline $200^{\circ} \mathrm{C}$ & $889 \mathrm{~kg} / \boldsymbol{m}^{3}$ \\ \hline $371^{\circ} \mathrm{C}$ & $860 \mathrm{~kg ...
CALCULATE the density of aqueous solutions of inorganic substances as a function of concentration and temperature using DENS1.
Notice that density is defined in terms of two dissimilar units, mass and volume. That means that density overall has derived units, just like velocity. Common units for density include g/mL, g/cm 3, g/L, kg/L, and even kg/m 3. Densities for some common substances are listed in Table \(\PageIndex{1}\).
Sodium weighs 0.968 gram per cubic centimeter or 968 kilogram per cubic meter, i.e. density of sodium is equal to 968 kg/m³; at 20°C (68°F or 293.15K) at standard atmospheric pressure . In Imperial or US customary measurement system, the density is equal to 60.43 pound per cubic foot [lb/ft³], or 0.5595 ounce per cubic inch [oz/inch³] .
Densities of Aqueous Solutions of Inorganic Sodium Salts Changes in density of aqueous solutions with changes in concentration at 20°C. Density of inorganic sodium salts in water is plotted as function of wt%, mol/kg water and mol/l solution.
