Yahoo Search Búsqueda en la Web

Resultado de búsqueda

  1. leetcode.com › problems › frog-jumpFrog Jump - LeetCode

    A frog is crossing a river. The river is divided into some number of units, and at each unit, there may or may not exist a stone. The frog can jump on a stone, but it must not jump into the water. Given a list of stones positions (in units) in sorted ascending order, determine if the frog can cross the river by landing on the last stone.

  2. 19 de oct. de 2013 · The goal is to find the earliest time when the frog can jump to the other side of the river. The frog can cross only when leaves appear at every position across the river from 1 to X. For example, you are given integer X = 5 and array A such that:

  3. Find the earliest time when a frog can jump to the other side of a river. Programming language: A small frog wants to get to the other side of a river. The frog is initially located on one bank of the river (position 0) and wants to get to the opposite bank (position X+1).

  4. 2 de oct. de 2021 · In this Leetcode Frog Jump problem solution, A frog is crossing a river. The river is divided into some number of units, and at each unit, there may or may not exist a stone. The frog can jump on a stone, but it must not jump into the water.

  5. Frog Jump II - You are given a 0-indexed integer array stones sorted in strictly increasing order representing the positions of stones in a river. A frog, initially on the first stone, wants to travel to the last stone and then return to the first stone.

  6. 13 de ago. de 2020 · Aug 13, 2020. -- A small frog wants to get to the other side of a river. The frog is initially located at one bank of the river (position −1) and wants to get to the other bank (position...

  7. 6 de ene. de 2017 · A frog is crossing a river. The river is divided into some number of units, and at each unit, there may or may not exist a stone. The frog can jump on a stone, but it must not jump into the water. Given a list of stones positions (in units) in sorted ascending order, determine if the frog can cross the river by landing on the last stone.